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May 7, 2017 at 5:39 comment added მამუკა ჯიბლაძე Minimally - one may reduce appeals to AC to the fact that any compact regular locale is spatial.
May 31, 2010 at 8:03 comment added Dmitri Pavlov @Mike: Yes, you are right. What I actually meant is that equivalence of categories of compact regular locales and compact regular (or Hausdorff) topological spaces requires some form of AC.
May 31, 2010 at 2:41 comment added Mike Shulman No, the categories of spatial locales and sober spaces are always equivalent. The reason that Tychonoff for locales doesn't imply Tychonoff for spaces is that the locale product of a family of spatial locales may no longer be spatial.
May 30, 2010 at 8:39 comment added Dmitri Pavlov @Martin: Tychonoff's theorem for locales does not require any form of the axiom of choice. However, the categories of spatial locales and sober topological spaces are equivalent only if AC is true.
May 30, 2010 at 8:07 comment added Martin Brandenburg Tychonoff and AC are equivalent in ZF.
May 30, 2010 at 7:02 history edited Andrej Bauer CC BY-SA 2.5
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May 30, 2010 at 6:55 history answered Andrej Bauer CC BY-SA 2.5