Timeline for Subset of a Hilbert scheme consisting of smooth subvarieties
Current License: CC BY-SA 3.0
2 events
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| Mar 10, 2017 at 15:56 | comment | added | abx | Yes. There is a universal subscheme $Z\subset X\times \mathrm{Hilb}(X)$, hence a proper map $Z\rightarrow \mathrm{Hilb}(X)$, and you are looking at the open subset of the base where the fiber is smooth. | |
| Mar 10, 2017 at 11:04 | history | asked | asv | CC BY-SA 3.0 |