Timeline for Does any smooth orbifold can be triangulated by orbi-simplex(triangulation of orbifolds)
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
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| Mar 21, 2017 at 6:32 | comment | added | Hao Yu | Is it true that any two triangulations are differed by a boundary of a higher dimensional simplicial complex(so we have a 'fundamental class' for closed smooth orbifold) | |
| Mar 14, 2017 at 15:38 | comment | added | Misha | No, a triangulable space need not be a manifold with corners (just take a look at the 1-dimensional case). | |
| Mar 14, 2017 at 4:06 | comment | added | Hao Yu | @Misha, you misunderstand what I am saying. OK, by definition, a space that is triangulable( which is homeomorphic to a simplicial complex), must be a manifold with corner, do you agree? But any orbifold won't be a manifold with corner. | |
| Mar 13, 2017 at 15:40 | comment | added | Misha | @HaoYu: You should state more precise question: Are you now assuming that your space is a domain in $R^n$? If so, you answered your own question (about interior being a manifold). In any case, if you have more questions, you should ask them separately, not as comments to an answer. | |
| Mar 13, 2017 at 7:16 | comment | added | Hao Yu | @Misha, the interior of an closed domain $\Omega$ in $R^{n}$ is just all the $\Omega$ minus the boundary $\partial \Omega$ . If a triangulated space is a manifold with boundary, the interior points are just the space excluding its boundary. By the definition of "triangulation" , it is a manifold with corners. | |
| Mar 12, 2017 at 15:37 | comment | added | Misha | @haoyu: What is the "interior of a triangulable space"? What do you mean by "interior of an orbifold"? | |
| Mar 12, 2017 at 4:33 | comment | added | haoyu | i feel orbifold should be triangulated by orbi simplex, but the paper proves that ordinary simplex is enough. surprised | |
| Mar 12, 2017 at 4:20 | comment | added | haoyu | ,I mean the interior of a triangulable space must be a topological manifold, right? (by the definition of triangulation), but if an orbifold can be triangulated by ordinary simplex, is the interior of any orbifold always a topological manifold? | |
| Mar 12, 2017 at 3:22 | comment | added | Misha | @haoyu: I do not understand what you are asking. | |
| Mar 9, 2017 at 21:33 | history | answered | Misha | CC BY-SA 3.0 |