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Mar 22, 2017 at 20:11 vote accept Snoop Catt
Mar 22, 2017 at 20:12
Mar 22, 2017 at 19:14 answer added Snoop Catt timeline score: 2
Mar 10, 2017 at 13:48 comment added YCor there's no Poisson-Furstenberg boundary for $G$, but for a pair $(G,\mu)$, $\mu$ being a probability measure.
Mar 10, 2017 at 10:47 answer added Colin Reid timeline score: 2
Mar 9, 2017 at 14:50 comment added YCor Subexponential growth implies amenable, by the same trivial argument as in the discrete case.
Mar 9, 2017 at 13:44 history asked Snoop Catt CC BY-SA 3.0