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Feb 9, 2020 at 17:21 history edited YCor
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Jun 29, 2010 at 17:28 comment added Matthew Conroy When $q \rightarrow \infty$, $P$ does not (generally) approach the circumcenter. Consider an obtuse isosceles triangle. If we let the obtuse angle approach $\pi$, the circumcircle radius grows to infinity, so the center grows arbitrarily far from the vertices of the triangle. Such a point clearly cannot minimize $f_q$. In this case, P approaches the midpoint of the side opposite the obtuse angle.
Jun 28, 2010 at 7:40 answer added Matthew Conroy timeline score: 3
Jun 27, 2010 at 21:09 history edited Andreas Rüdinger CC BY-SA 2.5
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May 30, 2010 at 8:11 answer added Suresh Venkat timeline score: 1
May 30, 2010 at 1:41 comment added S. Carnahan Don't you lose convexity when $q$ is small? It seems like you would get local minima near each corner in the zero limit.
May 29, 2010 at 22:58 history asked Andreas Rüdinger CC BY-SA 2.5