Timeline for Extensions of modules
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 14, 2017 at 12:30 | comment | added | M T | It is certainly false without the commutativity assumption. Take $R$ to be the quiver algebra $1 \stackrel{\alpha}\to 2 \stackrel \beta \to 3 \stackrel \gamma \to 4$ modulo $\beta\alpha=0$, $N_1=S_2, N_2=S_1, M_1=S_4, M_2=S_3$. | |
| Mar 15, 2017 at 11:58 | comment | added | Echeru | Yes, $R$ can be assumed to be commutative. But I suspect now the conclusion does not hold... | |
| Mar 12, 2017 at 23:22 | comment | added | Dag Oskar Madsen | Do you assume $R$ is commutative (since you are using the ac.commutative-algebra tag)? | |
| Mar 6, 2017 at 15:37 | review | First posts | |||
| Mar 6, 2017 at 15:47 | |||||
| Mar 6, 2017 at 15:34 | history | asked | Echeru | CC BY-SA 3.0 |