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Mar 4, 2017 at 18:37 comment added Michael Stoll @User0829 $-x/y$ is certainly not canonical, as $x$ and $y$ themselves are not. But if you want a uniformizer of a simple form, then (a constant multiple of) $x/y$ is the simplest function that vanishes to order 1 at infinity that you can come up with. The minus sign makes the standard invariant differential look like $(1 + \dots) dt$, when $t = -x/y$.
Mar 4, 2017 at 18:31 comment added Michael Stoll @JoeSilverman Sorry, I had somehow overlooked the "odd prime" requirement.
Mar 4, 2017 at 14:28 comment added User0829 Moreover, is there a canonical way of choosing local parameters $\pi_O$ and $\pi_P$ at $O$ and $P_{\neq O}\in E[\ell]$ respectively so that $\pi_O\mapsto \pi_P$ under the induced ring homomorphism $\mathcal{O}_O\to\mathcal{O}_P$ from the $\ell$-isogeny $E\xrightarrow{[\ell]}E$.
Mar 4, 2017 at 14:24 comment added User0829 Thank you very much. In fact, I have one more (stupid) question: I have read many literature choosing $-x/y$ as a local parameter at $O$. Is there any particular reason for that? I mean, is $-x/y$ `canonical' in some sense?
Mar 4, 2017 at 13:34 vote accept User0829
Mar 3, 2017 at 22:29 comment added Joe Silverman @MichaelStoll Very true, and more generally if $P$ is a point of order $m$ with $m$ even, one has to be more careful. But the question specified that $\ell$ is a prime that is at least $3$.
Mar 3, 2017 at 22:01 comment added Michael Stoll If $P$ is of order 2, then one should take $y$ instead (since then $x-a$ has order 2 at $P$).
Mar 3, 2017 at 20:30 history answered Joe Silverman CC BY-SA 3.0