Timeline for An extremal problem
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
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| Feb 27, 2017 at 16:55 | comment | added | djole | In my question there is one $3$. If instead of $3$ we put any constant greater than 3, then the minimum of the functional will not be attained for $f(x)\equiv x$/ | |
| Feb 27, 2017 at 16:53 | comment | added | Rodrigo de Azevedo | $3$? What constant $a$ are you referring to? | |
| Feb 27, 2017 at 16:46 | comment | added | djole | &Rodrigo de Azevedo. Instead of $3$ you can put any constant $a$, and $f(x)=x$ will be solution of Euler-Lagrange ODE. However it seems only for the constant $a=3$, it is true this. So "Proving that it minimizes the functional is left as an exercise for the reader" is impossible mission:) | |
| Feb 27, 2017 at 11:57 | history | edited | Rodrigo de Azevedo | CC BY-SA 3.0 |
Minor improvements
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| Feb 27, 2017 at 11:46 | history | answered | Rodrigo de Azevedo | CC BY-SA 3.0 |