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Feb 26, 2017 at 18:07 comment added Adam Differentiating the integral formula, I get $du(t)=e^{\int_{t_0}^{t} a(s)ds}a(t) dt\cdot u(t_0)+\sigma(t)dz$. How do I reconcile it with $du=a(t)u(t)dt+\sigma(t)dz$? (I only see that when t is infinitesimally close to $t_0.$)
Feb 26, 2017 at 3:50 history answered JGWang CC BY-SA 3.0