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Feb 24, 2017 at 9:10 comment added Joris Bierkens As far as I am aware the fractional Brownion motion will not satisfy the Markov property, so even if you can make sense of the diffusion equation (how?), it will not be Markovian. Therefore I would guess it will not be the limit of a Markov chain, as such a limit would be Markovian. Unless, perhaps, you consider limits of 'higher order' Markov chains, e.g. a Markov chain in $\mathbb R^d$, and consider the limit of e.g. the first component.
Feb 23, 2017 at 20:25 history asked KNN CC BY-SA 3.0