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Jun 15, 2020 at 7:27 history edited CommunityBot
Commonmark migration
Feb 23, 2017 at 22:32 comment added Pietro Majer To be precise, the Banach model spaces are isomorphic on any connected component of $X$. In any case, you do not need the Zorn lemma or variations of it to ensure the existence of a maximal atlas containing a given atlas $\mathcal{A}$: it is the union of all atlases compatible with $\mathcal{A}$ (a proper class, so what? :) )
Feb 23, 2017 at 19:53 comment added Ben McKay Why do you need to use different Banach spaces and linear functions for different charts on the same manifold? Surely you can fix the Banach space, and fix some sequence of linear functions for your corners, using only finitely many in each chart.
Feb 23, 2017 at 19:41 history asked Rubertos CC BY-SA 3.0