Timeline for Relation between curl and tensor divergence
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 18, 2018 at 19:09 | vote | accept | eyeballfrog | ||
| Feb 22, 2017 at 6:04 | comment | added | eyeballfrog | Actually I think that does it. $\nabla^2 \mathbf{u} = \boldsymbol \nabla( \boldsymbol \nabla\cdot\mathbf{u}) - \boldsymbol\nabla \times (\boldsymbol\nabla \times \mathbf{u}) $. If we assume $\boldsymbol \nabla\cdot \mathbf{u} = 0$, then $\mathbf{u}$ simply has to satisfy $\boldsymbol \nabla\times\mathbf{u} = - \mathbf{A}$, which is easily solved. | |
| Feb 22, 2017 at 4:00 | history | answered | Michael Renardy | CC BY-SA 3.0 |