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Feb 24, 2017 at 12:20 vote accept Archimondain
Feb 22, 2017 at 18:07 answer added Archimondain timeline score: 3
Feb 22, 2017 at 11:27 comment added Archimondain The ordinal $\alpha$ is not the largest of $J_{\alpha+1}$: The ordinals of some class $J_{\beta+1}$ are all those strictly smaller than $\omega \beta + \omega$ (this is the Jensen hierarchy and not Godel's one). Also at the end I simply consider the exemple where $\alpha = \omega_1$.
Feb 22, 2017 at 10:23 comment added Mohammad Golshani That $\alpha$ is simply definable in $J_{\alpha+1}$ does not follow from the simple fact that it is the largest ordinal in the structure? I don't understand how you transfer from $J_{\alpha+1}$ to $J_{\omega+1}$: You claim $\alpha$ is $\Sigma_2$-definable in $J_{\alpha+1}$, and then conclude the same in $J_{\omega_1+1}$, but how this is possible without referring to $\alpha$ itself?
Feb 21, 2017 at 16:27 history asked Archimondain CC BY-SA 3.0