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Feb 19, 2017 at 14:34 vote accept User 101794987
Feb 19, 2017 at 14:30 answer added Joël timeline score: 2
Feb 19, 2017 at 14:17 comment added User 101794987 @Joël, I am interested in the case when $k$ is odd, and $\varepsilon$ non-trivial. Thanks for pointing this out.
Feb 19, 2017 at 14:12 comment added Joël If $k$ is even, $p^{(k-2)/2} \in \mathbb Q$, so the answer is "always" in this case. So basically you're interested in the case of odd weight with necessarily non-trivial $\epsilon$. Is it how you intended the question? Or perhaps did you mean it with $(k-2)$ replaced by $(k-1)$?
Feb 19, 2017 at 13:28 history edited User 101794987 CC BY-SA 3.0
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Feb 19, 2017 at 13:23 history edited User 101794987 CC BY-SA 3.0
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Feb 19, 2017 at 1:45 review First posts
Feb 19, 2017 at 2:04
Feb 19, 2017 at 1:37 history asked User 101794987 CC BY-SA 3.0