Timeline for Must a prime power of the form 16t^2+1 be a prime?
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 17, 2017 at 1:20 | vote | accept | smart cat | ||
| Feb 17, 2017 at 1:11 | answer | added | smart cat | timeline score: 2 | |
| S Feb 16, 2017 at 23:56 | history | suggested | Amir Sagiv | CC BY-SA 3.0 |
latex edits + english
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| Feb 16, 2017 at 23:48 | review | Suggested edits | |||
| S Feb 16, 2017 at 23:56 | |||||
| Feb 16, 2017 at 22:18 | answer | added | Aaron Meyerowitz | timeline score: 13 | |
| Feb 16, 2017 at 22:07 | comment | added | Gerhard Paseman | You might add that as an answer. Further, if there are other MathOverflow questions which use the same reference to Cohn for similar questions, you might link to them. Gerhard "Building Better Bridges For Everyone" Paseman, 2017.02.16. | |
| Feb 16, 2017 at 21:55 | comment | added | smart cat | Thank you so much. With the referene you mentioned, I found a comprehensive treatment on this problem by J. H. E. Cohn ( "The diophantine equation x^2 + C = y^n", Acta Arithmetica,1993 ). More precisely, x^2+1=y^n has no solution for x, y being positive integers and n greater than or equal to 3. Now, this question is closed. | |
| Feb 16, 2017 at 20:26 | comment | added | Gerhard Paseman | I think Granville has a result that shows r is either 1 or less than 6 for q^r -1 a square. See arxiv.org/abs/1212.6306 for his result and applicability to your problem. Gerhard "At Least It's A Start" Paseman, 2017.02.16. | |
| Feb 16, 2017 at 20:18 | review | First posts | |||
| Feb 16, 2017 at 20:28 | |||||
| Feb 16, 2017 at 20:17 | history | asked | smart cat | CC BY-SA 3.0 |