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Feb 16, 2017 at 13:02 comment added Tony Huynh Nice question. The original problem follows from Grötzsch's Theorem, but that is a bit like killing a mosquito with a cannon.
Feb 15, 2017 at 19:54 comment added Ben Barber An alternative construction to that given below is to draw a $K_5$ in the conventional fashion then delete two non-adjacent boundary pieces. The inner cycle has a unique $3$-colouring $12123$ up to isomorphism, and then the points of the star are coloured $33312$, with one of the pairs of $3$'s adjacent. This also uses $8$ lines, which makes me wonder if there's a construction that uses fewer.
Feb 15, 2017 at 18:33 vote accept Fedor Petrov
Feb 15, 2017 at 18:28 answer added Thomas Bloom timeline score: 12
Feb 15, 2017 at 16:51 history edited Fedor Petrov CC BY-SA 3.0
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Feb 15, 2017 at 16:37 history edited Fedor Petrov CC BY-SA 3.0
added 7 characters in body
Feb 15, 2017 at 15:59 history asked Fedor Petrov CC BY-SA 3.0