Timeline for Origami Constructions: Intersecting two Circles
Current License: CC BY-SA 2.5
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 9, 2010 at 21:05 | comment | added | Bart Snapp | Alperin has informed me that if you want an elegant folding solution, one should intersect parabolas instead of circles. | |
| Jun 3, 2010 at 17:22 | vote | accept | CommunityBot | ||
| Jun 3, 2010 at 17:22 | history | bounty ended | Bart Snapp | ||
| Jun 2, 2010 at 3:03 | comment | added | Bart Snapp | Good idea - I just sent him an email. I've also emailed Thomas Hull and Hatori, Koshiro - but they did not know of a simple construction either. | |
| Jun 1, 2010 at 22:14 | comment | added | Cam McLeman | Ah, you're right. I misread the bolded text in 6.1 as an algorithm. While this isn't quite as explicit as I would have hoped, Alperin's "A Mathemtical Theory of Origami Constructions and Numbers" contains in Section 4 a proof that intersections of conics are origami-constructible. I'm not sure how hard it would be to do explicitly by following the proof. Perhaps the best solution is to email Alperin directly. | |
| Jun 1, 2010 at 13:42 | comment | added | Bart Snapp | While I am often mistaken, it appears that in Section 6 of Alperin's "Mathematical Origami: Another View of Alhazen's Optical Problem," he merely states that it is an interesting problem to give elegant origami constructions for the intersection of two conics. No elegant solution is given (or at least I cannot find one). | |
| May 28, 2010 at 1:42 | history | answered | Cam McLeman | CC BY-SA 2.5 |