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Apr 13, 2017 at 12:58 history edited CommunityBot
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Feb 14, 2017 at 2:37 comment added gradstudent Lets say it this way : Is there any inequality version of the Sperner's theorem? Like saying "At most so many solutions can be found on the $\{-1,1\}^n$ of the inequation $\vec{a}.\vec{x} < b$". Then say I am trying to count solutions to such inequations that live on the $p$ dimensional faces.
Feb 14, 2017 at 1:16 comment added Pat Devlin That still doesn't make sense to talk about "probability." As for extremal bounds, some hyperplanes (e.g., $x_1 =1$) contain faces entirely, and some (e.g., $x_1 =0$) cut things in half very neatly. What more specifically are you really trying to ask? (Perhaps it would help us understand what you want if you describe your motivation.)
Feb 13, 2017 at 22:16 history edited gradstudent CC BY-SA 3.0
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Feb 13, 2017 at 22:10 comment added gradstudent Maybe this is a way to think of what I am trying to convey : Fix the choice of $\vec{a}$ and $\vec{b}$. Now can one show that there is an universal upper bound on the probabilities I am looking for? (...for example see what happens in say the Sperner's Theorem..there is an universal upperbound on the number of solutions of a linear equation on the discrete hypercube and that upperbound doesn't depend on the $\vec{a}$ or $b$ that one starts with..)
Feb 13, 2017 at 20:53 comment added Robert Israel In that case, there is no uniform random choice. You would need to specify the distribution. And if that distribution allows $b$ to be large compared to $|\vec{a}|$, it is very likely that the hyperplane will miss your hypercube entirely.
Feb 13, 2017 at 20:22 comment added gradstudent By "hyperplane" I mean any affine space. Consider any function of the form, $\vec{a}.\vec{x}+b =0$.
Feb 13, 2017 at 19:33 comment added Robert Israel Do you mean a hyperplane through the origin? Otherwise, there's no such thing as a random hyperplane.
Feb 13, 2017 at 16:40 history edited gradstudent CC BY-SA 3.0
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Feb 13, 2017 at 16:34 history asked gradstudent CC BY-SA 3.0