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Apr 13, 2017 at 12:19 history edited CommunityBot
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Feb 23, 2017 at 20:39 vote accept Wilson Forero
Feb 16, 2017 at 19:52 answer added Wilson Forero timeline score: 0
Feb 14, 2017 at 7:43 comment added მამუკა ჯიბლაძე Use the fact that $f_i(\lambda(x,m))=\lambda_i(f_i(x),m)$ (where $\lambda_i$ is the action of $M$ on $Y_i$)
Feb 14, 2017 at 1:11 comment added Wilson Forero I writed a note whit the reason why I think can´t repeated verbatim the proof
Feb 14, 2017 at 1:05 history edited Wilson Forero CC BY-SA 3.0
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Feb 13, 2017 at 18:06 comment added მამუკა ჯიბლაძე Look at the Example 15.3(2) (page 259); it is done for sets there but can be repeated verbatim for $M$-sets.
Feb 13, 2017 at 15:09 history edited Wilson Forero CC BY-SA 3.0
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Feb 13, 2017 at 15:04 history asked Wilson Forero CC BY-SA 3.0