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Alex M.
Alex M.
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Theorem 3 Theorem 3 in "On majorization and Schur products" by Bapat and Sunder provides a stronger result. Take A=B=K$A=B=K$ and specialize to k=1$k=1$ in the majorization.

Theorem 3 provides a stronger result. Take A=B=K and specialize to k=1 in the majorization.

Theorem 3 in "On majorization and Schur products" by Bapat and Sunder provides a stronger result. Take $A=B=K$ and specialize to $k=1$ in the majorization.

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AHusain
AHusain
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Theorem 3 provides a stronger result. Take A=B=K and specialize to k=1 in the majorization.