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Feb 21, 2023 at 14:17 comment added user494312 Is there a positive result that under some assumptions $\text{Sing} X$ is full? e.g. that for CW complexes $X$ and $Y$ $Hom_{Top}(X,Y)=Hom_{sSets}(Sing X, Sing Y)$?
May 20, 2019 at 9:43 comment added Denis Nardin @StefanoNicotra It might be false, you're right that looking at it today it seems a lot fishier to me (maybe I was thinking of homotopical Kan extensions when I wrote that comment...). In particular the counit is almost certainly $|\mathrm{Sing}X|→X$...
May 20, 2019 at 9:40 comment added Stefano Nicotra @DenisNardin Is that true? I thought that every numerically generated space was a canonical colimit over ∆, where we consider all possible morphisms between standard simplices and not just the realisations of the ones coming from ∆. Besides, unless I'm missing something, the Kan extension described in the Question should be just |Sing(X)|, which is a CW-complex so any topological space which is not a CW-complex should be a counterexample (and even if you start with a CW-complex you usually end up with a much bigger one after applying |Sing(-)|).
Apr 13, 2017 at 12:19 history edited CommunityBot
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Mar 27, 2017 at 11:32 answer added Peter LeFanu Lumsdaine timeline score: 6
Feb 11, 2017 at 8:40 history edited user24453 CC BY-SA 3.0
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Feb 11, 2017 at 4:04 comment added Denis Nardin I suspect that the left Kan extension is the identity for numerically generated spaces (which are the kind of spaces you want to consider in homotopy theory anyway).
Feb 11, 2017 at 3:50 history asked user24453 CC BY-SA 3.0