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Feb 11, 2017 at 14:21 comment added David Handelman This boils down to the use of ${\bf N}$ to denote the positive integers (my use) or the nonnegative integers (your use); I prefer using $\bf Z^+$ for the latter, which avoids some ambiguity ... (and although it is nonstandard, $\bf Z^{++}$ for the positive integers avoids more ambiguity).
Feb 11, 2017 at 14:13 comment added Todd Trimble Well, I say there is an $e_0$ because $0$ is a natural number (belongs to $\mathbf{N}$). But it's not important here.
Feb 10, 2017 at 14:08 comment added David Handelman Easier is $T^* : e_i \mapsto e_{i-1}$ if $i > 1$, and $T^*e_1 = 0$ (there is no $e_0$).
Feb 9, 2017 at 22:46 comment added Todd Trimble @GerryMyerson For (a) one doesn't have to be so fancy, but it could be the ring of bounded linear maps taking $l^2$ to itself, with multiplication given by composition. Here $y$ would be given by $T$, and $x$ by $e_0 \mapsto e_0$ and $e_{i+1} \mapsto e_i$.
Feb 9, 2017 at 22:01 comment added Gerry Myerson Where is the ring?
S Feb 9, 2017 at 21:43 history answered David Handelman CC BY-SA 3.0
S Feb 9, 2017 at 21:43 history made wiki Post Made Community Wiki by David Handelman