Timeline for Symmetric group acting on the set of boolean functions
Current License: CC BY-SA 3.0
4 events
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Jun 27, 2017 at 8:14 | comment | added | Ashot | One question. $\binom n2 2^{2^{n-1}}\cdot 3^{2^{n-2}}$ is number of orbits when a single two-cycle acts on the set of boolean functions, right? By Cauchy-Frobenius lemma we should add number of functions that a group element leaves unchanged. I am missing something? | |
Feb 5, 2017 at 20:36 | history | edited | Richard Stanley | CC BY-SA 3.0 |
corrected formula for $p$
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Feb 5, 2017 at 20:03 | vote | accept | Ashot | ||
Feb 5, 2017 at 19:30 | history | answered | Richard Stanley | CC BY-SA 3.0 |