Skip to main content
4 events
when toggle format what by license comment
Jun 27, 2017 at 8:14 comment added Ashot One question. $\binom n2 2^{2^{n-1}}\cdot 3^{2^{n-2}}$ is number of orbits when a single two-cycle acts on the set of boolean functions, right? By Cauchy-Frobenius lemma we should add number of functions that a group element leaves unchanged. I am missing something?
Feb 5, 2017 at 20:36 history edited Richard Stanley CC BY-SA 3.0
corrected formula for $p$
Feb 5, 2017 at 20:03 vote accept Ashot
Feb 5, 2017 at 19:30 history answered Richard Stanley CC BY-SA 3.0