Timeline for Two combinatorial identities
Current License: CC BY-SA 3.0
12 events
when toggle format | what | by | license | comment | |
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Feb 6, 2017 at 2:54 | vote | accept | Si-Qi Liu | ||
Feb 5, 2017 at 18:59 | comment | added | Pietro Majer | Yes; but I suspected the wanted identity may be different (see my first comment) | |
Feb 5, 2017 at 17:59 | answer | added | Vladimir Dotsenko | timeline score: 5 | |
Feb 5, 2017 at 17:54 | comment | added | Fedor Petrov | @PietroMajer I doubt. This identity is telescoping and Vandermonde's is not (or at least I do not know how it is). | |
Feb 5, 2017 at 16:25 | answer | added | user64494 | timeline score: 1 | |
Feb 5, 2017 at 14:55 | answer | added | Fedor Petrov | timeline score: 6 | |
Feb 5, 2017 at 9:09 | comment | added | Pietro Majer | I guess dividing by ${ {\alpha+\beta\over\beta} l \choose l}$ both sides in the first identity should give a Vandermonde's identity en.wikipedia.org/wiki/Vandermonde%27s_identity | |
Feb 5, 2017 at 8:32 | comment | added | Pietro Majer | In the RHS of the first identity, do you have $\alpha kl $ or rather $\beta kl$? I would expect something depending only on ${\alpha+\beta\over\beta}$, not on $\alpha$ or $\beta$, since so is the LHS. | |
S Feb 5, 2017 at 7:20 | history | suggested | Amir Sagiv | CC BY-SA 3.0 |
english edits
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Feb 5, 2017 at 7:11 | review | Suggested edits | |||
S Feb 5, 2017 at 7:20 | |||||
Feb 5, 2017 at 5:43 | review | First posts | |||
Feb 5, 2017 at 7:11 | |||||
Feb 5, 2017 at 5:39 | history | asked | Si-Qi Liu | CC BY-SA 3.0 |