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Martin Sleziak
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The Green-Tao theorem states that for every $n$, there is an arithmetic sequence of length $n$ consisting of primes.

For primes, $p$, let $P(p)$ be the maximum length of an arithmetic progression of primes whose least element is $p$.

Is it known whether $P(p)=p$ for every prime?

(This clearly generalizes the Green-Tao theorem, asserting that long progressions show up "as soon as possible." Note that $P(p) \leq p$ by viewing the progression mod $p$.)

The Green-Tao theorem states that for every $n$, there is an arithmetic sequence of length $n$ consisting of primes.

For primes, $p$, let $P(p)$ be the maximum length of an arithmetic progression of primes whose least element is $p$.

Is it known whether $P(p)=p$ for every prime?

(This clearly generalizes the Green-Tao theorem, asserting that long progressions show up "as soon as possible." Note that $P(p) \leq p$ by viewing the progression mod $p$.)

The Green-Tao theorem states that for every $n$, there is an arithmetic sequence of length $n$ consisting of primes.

For primes, $p$, let $P(p)$ be the maximum length of an arithmetic progression of primes whose least element is $p$.

Is it known whether $P(p)=p$ for every prime?

(This clearly generalizes the Green-Tao theorem, asserting that long progressions show up "as soon as possible." Note that $P(p) \leq p$ by viewing the progression mod $p$.)

Reworded parts for slight clarity and added the reference to the Green-Tao theorem.
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By a famousThe Green-Tao theorem forstates that for every $n$, there is an arithmetic sequence of length $n$ consisting of primes.

LetFor primes, $P(n)$$p$, let $P(p)$ be the maximum length of an arithmetic progression of primes such that thewhose least element is $n$, has it been proven or disproven that $P(p)=p$ for every prime? If true this$p$.

Is it known whether $P(p)=p$ for every prime?

(This clearly generalizes the aboveGreen-Tao theorem, asserting that long progressions show up "as soon as possible." Note that $P(p) \leq p$ by viewing the progression mod $p$.)

By a famous theorem for every $n$ there is an arithmetic sequence of length $n$ consisting of primes.

Let $P(n)$ be the maximum length of an arithmetic progression of primes such that the least element is $n$, has it been proven or disproven that $P(p)=p$ for every prime? If true this clearly generalizes the above theorem.

The Green-Tao theorem states that for every $n$, there is an arithmetic sequence of length $n$ consisting of primes.

For primes, $p$, let $P(p)$ be the maximum length of an arithmetic progression of primes whose least element is $p$.

Is it known whether $P(p)=p$ for every prime?

(This clearly generalizes the Green-Tao theorem, asserting that long progressions show up "as soon as possible." Note that $P(p) \leq p$ by viewing the progression mod $p$.)

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Gorka
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By a famous theorem for every $n$ there is an arithmetic sequence of length $n$ consisting of primes.

Let $P(n)$ be the maximum length of an arithmetic progression of primes such that the least element is $n$, has it been proven or disproven that $P(p)=p$ for every prime? If true this clearly generalizes the above theorem.

By a famous theorem for every $n$ there is an arithmetic sequence of length $n$ consisting of primes.

Let $P(n)$ be the maximum length of an arithmetic progression of primes, has it been proven or disproven that $P(p)=p$ for every prime? If true this clearly generalizes the above theorem.

By a famous theorem for every $n$ there is an arithmetic sequence of length $n$ consisting of primes.

Let $P(n)$ be the maximum length of an arithmetic progression of primes such that the least element is $n$, has it been proven or disproven that $P(p)=p$ for every prime? If true this clearly generalizes the above theorem.

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Gorka
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