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Apr 23, 2017 at 18:03 vote accept Saal Hardali
Jun 8, 2023 at 14:58
Feb 2, 2017 at 18:39 comment added Matthias Wendt Yes, $\pi_\ast$ and $\pi^\ast$ exist in the unbounded setting. I'm not so sure about the exceptional functors. In a sense, having the exceptional induction $Ind_!$ only in the case of subgroup inclusions and not for arbitrary homomorphisms doesn't seem that much of a restriction - do we really need induction in more general cases? The exceptional functors probably exist whenever the groups involved have finite cohomological dimension (and I suppose there are enough interesting groups with that property).
Feb 2, 2017 at 18:09 comment added Saal Hardali It seems to me like the story should be that $\pi_*$ and $\pi^*$ always exist in the unbounded derived category (once correctly defined as you say). Then $\pi_!$ and $\pi^!$ exist for certain good situation. Formally in an ideal situation (by brown representability) to get a $\pi^!$ the $\pi_*$ should preserve arbitrary coproducts and to get a $\pi_!$ the $\pi^*$ should preserve arbitrary products. Does it look to you something like this holds in this case? (at least for discrete groups).
Feb 2, 2017 at 16:10 vote accept Saal Hardali
Feb 2, 2017 at 17:52
Feb 1, 2017 at 18:22 history bounty ended CommunityBot
Jan 25, 2017 at 10:06 history edited Matthias Wendt CC BY-SA 3.0
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Jan 24, 2017 at 22:19 history edited Matthias Wendt CC BY-SA 3.0
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Jan 24, 2017 at 19:50 history answered Matthias Wendt CC BY-SA 3.0