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Feb 13, 2017 at 12:06 answer added rozu timeline score: 3
Jan 23, 2017 at 8:47 comment added Longyearbyen Thank you. Your example works. If you want to write it as an answer, I ll be glad to accept it and vote it up.
Jan 22, 2017 at 22:44 comment added Pablo Shmerkin This is sort of cheating, but isn't a (separated) countable union of spheres of radii tending to $0$ a counterexample? There should also be more natural examples. After all, the outer measures $\mathcal{H}_\delta^m$ are highly non-additive.
Jan 22, 2017 at 18:37 comment added Anthony Quas Sorry - I didn't read your question properly.
Jan 22, 2017 at 18:28 comment added Longyearbyen But why should this set be Borel?
Jan 22, 2017 at 18:24 comment added Anthony Quas $\mathcal H^1_\delta$-measurable?
Jan 22, 2017 at 17:45 comment added Longyearbyen Thank you for your interest in this question. I am not sure to have got your point. When you say "non measurable" what measaure do you think about?
Jan 22, 2017 at 17:11 comment added Anthony Quas Doesn't a non-measurable one-dimensional subset of the real line, thought of as a subset of $\mathbb R^2$ give an immediate counterexample?
Jan 22, 2017 at 13:35 history edited Longyearbyen CC BY-SA 3.0
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Jan 22, 2017 at 1:40 history asked Longyearbyen CC BY-SA 3.0