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Jan 20, 2017 at 12:10 comment added Jason Starr By codimension I really meant the height of the corresponding prime ideal. You are correct that I should localize the ring $R$ at the maximal ideal $\mathfrak{m}$. Since the finitely generated $R$-module $S/R$ is annihilated by $\mathfrak{m}$, for every prime ideal $\mathfrak{p}$ with $\mathfrak{p}\subsetneq \mathfrak{m}$, the localization $R_{\mathfrak{p}}$ equals $S_{\mathfrak{p}}$. Thus $R_{\mathfrak{p}}$ is regular for all prime ideals $\mathfrak{p}R_{\mathfrak{m}}$ of $R_\mathfrak{m}$ except the maximal ideal.
Jan 20, 2017 at 12:07 vote accept Cusp
Jan 20, 2017 at 11:30 comment added Cusp Here by codimension did you mean embedding dimension (maximal homogeneous ideal ) minus dim R?
S Jan 20, 2017 at 10:02 history answered Jason Starr CC BY-SA 3.0
S Jan 20, 2017 at 10:02 history made wiki Post Made Community Wiki by Jason Starr