Timeline for When do almost all these invariants of tensors vanish?
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
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| Jun 15, 2020 at 7:27 | history | edited | CommunityBot |
Commonmark migration
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| Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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| Feb 1, 2017 at 2:41 | comment | added | Will Sawin | @KeD In the general version I want the answer for arbitrary $\alpha_0,\dots,\alpha_15$. That might be too much to ask! I would be interested even in the answer for a single new case (new modulo the symmetries of the problem, of course). | |
| Feb 1, 2017 at 2:38 | comment | added | KeD | Hi @WillSawin, what are the $\alpha_i$'s in the general version of the combinatorial problem? | |
| Jan 20, 2017 at 15:05 | comment | added | Abdelmalek Abdesselam | @user44191: what do you mean by $i_{m,A}(x)$? If this is the determinant map $(A^{\otimes m})^{\otimes n^m}\rightarrow k$ then the result on $x\in A$ is identically zero. | |
| Jan 20, 2017 at 7:14 | comment | added | user44191 | Is there any specific reason not to look at the simpler question of: What is the set of elements of $A$ such that for all but finitely many $m, i_{m, A}(x) = 0$? If I'm not mistaken, it should answer your question directly, too, no? | |
| Jan 20, 2017 at 3:43 | comment | added | Will Sawin | @SylvainJULIEN The second one. Fixed now. | |
| Jan 20, 2017 at 3:43 | history | edited | Will Sawin | CC BY-SA 3.0 |
added 1 character in body
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| Jan 19, 2017 at 21:00 | comment | added | Sylvain JULIEN | +1 for the probably unintended pun with M&M's. More seriously, do you mean $ \sigma(x)x $ or $ \sigma(x)-x $? | |
| Jan 19, 2017 at 20:12 | history | edited | Abdelmalek Abdesselam | CC BY-SA 3.0 |
fixed spelling of my name :)-
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| Jan 19, 2017 at 18:28 | history | asked | Will Sawin | CC BY-SA 3.0 |