Timeline for does a line bundle always have a degree
Current License: CC BY-SA 2.5
9 events
| when toggle format | what | by | license | comment | |
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| May 1, 2018 at 13:45 | comment | added | Ben Webster♦ | @Luke Why are you writing this here instead of the question? I think the OP was just being sloppy and not worrying about non-normal curves. I think my answer about Cartier divisors is still fine. | |
| May 1, 2018 at 5:54 | comment | added | Luke | This may be a long shot since the question is so old, but I was hoping to clarify something. I don't normally post on MathOverflow since I'm only a student, so bear with me. The question says "for curves there is a very simple notion of degree of a line bundle or equivalently of a Weil or Cartier divisor". Does this means specifically non-singular curves? In the non-singular case you have that it is locally factorial, so you get a Weil/Cartier correspondence. But in general, how do you get a notion of degree for Cartier divisors? Indeed in general, the curve may not even be normal, right? | |
| Oct 1, 2010 at 23:30 | history | edited | Ben Webster♦ | CC BY-SA 2.5 |
added 20 characters in body
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| Oct 12, 2009 at 23:40 | vote | accept | solbap | ||
| Oct 10, 2009 at 21:30 | comment | added | Ben Webster♦ | You have to look at arbitrarily large n. Each one lets you see the reduction of the Chern class mod n. | |
| Oct 10, 2009 at 18:39 | comment | added | solbap | So in the algebraic version of the exponential sequence what do you take as n? Is it the dimension of the space? | |
| Oct 10, 2009 at 18:37 | vote | accept | solbap | ||
| Oct 10, 2009 at 18:37 | |||||
| Oct 10, 2009 at 18:36 | vote | accept | solbap | ||
| Oct 10, 2009 at 18:37 | |||||
| Oct 10, 2009 at 13:57 | history | answered | Ben Webster♦ | CC BY-SA 2.5 |