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Jun 1, 2017 at 6:47 comment added Pietro Majer Actually the sense of the approach was just trying to use an integral representation for $F''$, since integrals have a rich calculus. The above formula is not too complicated, so I think it's doable; yet I hoped for a quick answer
May 27, 2017 at 0:35 comment added fedja @PietroMajer I tried to see if one can make sense of your approach today. Basically, it boils down to this: what "convenient" operators $L$ satisfy $Lf_t\ge 0$ for every function $f_t(s)=s^2e^{-ts}$ ($t>0$, $s$ large positive). Alas, my answer was "I have no idea". Can you think of a single one that can be used to prove any non-obvious convexity property of the desired type?
Jan 18, 2017 at 16:31 history edited Pietro Majer CC BY-SA 3.0
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Jan 17, 2017 at 10:51 history edited Pietro Majer CC BY-SA 3.0
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Jan 17, 2017 at 4:06 comment added T. Amdeberhan This is a fascinating approach! I wonder how to achieve positivity.
Jan 17, 2017 at 3:28 history answered Pietro Majer CC BY-SA 3.0