Skip to main content
8 events
when toggle format what by license comment
Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Jan 15, 2017 at 16:27 vote accept Noah Schweber
Jan 15, 2017 at 15:57 answer added Joel David Hamkins timeline score: 5
Jan 15, 2017 at 12:14 comment added Joel David Hamkins I was merely responding to your statement, "...resurrecting the measurability of a smaller cardinal. If that's even possible...". It is possible, by Kunen's theorem. I agree that this does not shed light on Noah's question.
Jan 15, 2017 at 12:10 comment added Asaf Karagila @Joel: Yes, by adding Cohen sets below the measurable, I know (and this way it ends up immune to Cohen sets). But never the less, this is a very different situation from taking an inner model which is an ultrapower by a measure.
Jan 15, 2017 at 12:00 comment added Joel David Hamkins @AsafKaragila Kunen showed long ago that a non-measurable cardinal can become measurable in a forcing extension, and the consistency strength is just a measurable cardinal. You start with $\kappa$ measurable, and then kill it in a way that it can be resurrected.
Jan 15, 2017 at 6:51 comment added Asaf Karagila Well, undoing an ultrapower means resurrecting the measurability of a smaller cardinal. If that's even possible, I'd imagine some very very large cardinals are involved; and the measure being something like some type of a huge measure or so.
Jan 15, 2017 at 3:22 history asked Noah Schweber CC BY-SA 3.0