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Jan 25, 2017 at 16:10 vote accept Karen Yeats
Jan 24, 2017 at 15:58 comment added Rudi Pendavingh The uniform matroid $U_{2,4}$ cannot be represented over $\{1,-1,i,-1\}$. Therefore, if $M$ is representable over $\{1,-1,i,-1\}$, then $M$ cannot have $U_{2,4}$ as a minor, hence $M$ is binary. But since such $M$ is also sixth-root, $M$ is ternary as well. Binary+ternary = regular.
Jan 23, 2017 at 15:39 comment added Karen Yeats Thanks Rudi. That is very helpful. Why is it true?
Jan 19, 2017 at 21:52 history edited Rudi Pendavingh CC BY-SA 3.0
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Jan 19, 2017 at 21:41 comment added Rudi Pendavingh $M$ is representable over $\{1,-1, i,-i\}$ if and only if $M$ is regular.
Jan 16, 2017 at 18:59 comment added Karen Yeats I think that explains very well why the 6th root of unity matroids are so important. Still, matroid classes like the {1,-1,i,-i} partial field representable ones would live inside the 6th root of unity matroids and it isn't clear to me what that subclass would look like.
Jan 14, 2017 at 19:26 history answered Rudi Pendavingh CC BY-SA 3.0