Timeline for matroids representable over root of unity partial fields that are not the 6th root of unity partial field
Current License: CC BY-SA 3.0
7 events
when toggle format | what | by | license | comment | |
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Jan 25, 2017 at 16:10 | vote | accept | Karen Yeats | ||
Jan 24, 2017 at 15:58 | comment | added | Rudi Pendavingh | The uniform matroid $U_{2,4}$ cannot be represented over $\{1,-1,i,-1\}$. Therefore, if $M$ is representable over $\{1,-1,i,-1\}$, then $M$ cannot have $U_{2,4}$ as a minor, hence $M$ is binary. But since such $M$ is also sixth-root, $M$ is ternary as well. Binary+ternary = regular. | |
Jan 23, 2017 at 15:39 | comment | added | Karen Yeats | Thanks Rudi. That is very helpful. Why is it true? | |
Jan 19, 2017 at 21:52 | history | edited | Rudi Pendavingh | CC BY-SA 3.0 |
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Jan 19, 2017 at 21:41 | comment | added | Rudi Pendavingh | $M$ is representable over $\{1,-1, i,-i\}$ if and only if $M$ is regular. | |
Jan 16, 2017 at 18:59 | comment | added | Karen Yeats | I think that explains very well why the 6th root of unity matroids are so important. Still, matroid classes like the {1,-1,i,-i} partial field representable ones would live inside the 6th root of unity matroids and it isn't clear to me what that subclass would look like. | |
Jan 14, 2017 at 19:26 | history | answered | Rudi Pendavingh | CC BY-SA 3.0 |