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Jan 17, 2017 at 19:46 answer added Jan-Christoph Schlage-Puchta timeline score: 1
Jan 17, 2017 at 18:34 comment added Jan-Christoph Schlage-Puchta @Anthony Quas: The set $J$ has not as much structure as the set $I$. It is not clear to me that is better to work with a simpler operation or a simpler set.
Jan 17, 2017 at 18:25 review Close votes
Jan 17, 2017 at 18:59
Jan 17, 2017 at 17:58 history edited BigM CC BY-SA 3.0
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Jan 13, 2017 at 12:21 history edited BigM CC BY-SA 3.0
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Jan 13, 2017 at 6:35 comment added Anthony Quas Why don't you just apply $\log(1+x)$ to $I$: $J=\log(1+I)$? Then you are asking about $J-J$ (or $\exp(J-J)$.
Jan 13, 2017 at 2:41 history asked BigM CC BY-SA 3.0