Timeline for The missing link: an inequality
Current License: CC BY-SA 3.0
16 events
| when toggle format | what | by | license | comment | |
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| Jan 10, 2017 at 23:03 | comment | added | Gerhard Paseman | Yes, but working with the g's is better (assuming the domain is (0,1)) as one does not have to deal with the 1/(1-x) factor in doing comparisons. Gerhard "Let The Physicists Subtract Infinities" Paseman, 2017.01.10. | |
| Jan 10, 2017 at 22:59 | comment | added | Pietro Majer | One can also write everything n terms of the h only: $$F_n''=\sum_{1\le i\le 4}h_{p_i} -\sum_{1\le i\le 4}h_{q_i} $$ with: $$p:=(2n+1,2n+1,4n,8n-2)$$ $$q:=(2n,2n+2,4n-1,4n+2)$$ maybe matching conveniently the good terms $(q)$ with the bad ones $(p )$ one can reduce the complexity | |
| S Jan 10, 2017 at 22:46 | history | suggested | CommunityBot | CC BY-SA 3.0 |
Sorry for multiple edits. I am the author of this answer and the edits (but not the original question!) -- in any case, the inequalities added recently are not valid (they fail for n=10,x=8/10).
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| Jan 10, 2017 at 22:14 | review | Suggested edits | |||
| S Jan 10, 2017 at 22:46 | |||||
| S Jan 10, 2017 at 22:12 | history | suggested | CommunityBot | CC BY-SA 3.0 |
Apologies for another edit -- I noticed that in the last "edit summary," I identified myself as the "author of the original question" -- I meant to indicate that I wrote the answer being edited; I am not the author of the question, and wanted to correct the record here.
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| Jan 10, 2017 at 21:53 | review | Suggested edits | |||
| S Jan 10, 2017 at 22:12 | |||||
| S Jan 10, 2017 at 21:23 | history | suggested | CommunityBot | CC BY-SA 3.0 |
Another added comment (note that I am the author of the original question -- I would prefer to use the site's commenting feature, but would rather not establish a permanent account).
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| Jan 10, 2017 at 21:09 | review | Suggested edits | |||
| S Jan 10, 2017 at 21:23 | |||||
| S Jan 10, 2017 at 19:23 | history | suggested | user103396 | CC BY-SA 3.0 |
Addenda, since I am apparently not able to comment (note: This edit was just rejected, but I am the original author of this answer.)
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| Jan 10, 2017 at 19:03 | review | Suggested edits | |||
| S Jan 10, 2017 at 19:23 | |||||
| S Jan 10, 2017 at 6:19 | history | suggested | user103396 | CC BY-SA 3.0 |
Fixed typos.
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| Jan 10, 2017 at 6:14 | comment | added | Gerhard Paseman | Upon reflection, it might be better to combine the two items giving the h term and come up with a j term (2d derivative of log of ( 1 - (x^{2n+1}/simple polynomial)). Gerhard "Term Rewriting For Better Living" Paseman, 2017.01.09. | |
| Jan 10, 2017 at 5:54 | comment | added | Gerhard Paseman | Do my eyes deceive me, or is it true that $g_m(-x)=h_m(x)$ for odd $m$? Gerhard "And Can We Use This?" Paseman, 2017.01.09. | |
| Jan 10, 2017 at 5:34 | review | Suggested edits | |||
| S Jan 10, 2017 at 6:19 | |||||
| Jan 10, 2017 at 5:26 | review | First posts | |||
| Jan 10, 2017 at 5:31 | |||||
| Jan 10, 2017 at 5:26 | history | answered | user103395 | CC BY-SA 3.0 |