Timeline for tighter bound on the sum of sub-matrices
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 8, 2017 at 16:13 | vote | accept | user103308 | ||
| Jan 8, 2017 at 15:59 | answer | added | Markus Sprecher | timeline score: 1 | |
| Jan 8, 2017 at 15:29 | comment | added | user103308 | each $v_i$ is a scalar, so $\sum_i A_i v_i$ is a weighted sum of matrices $A_1,\ldots, A_n$. | |
| Jan 8, 2017 at 15:27 | comment | added | user35593 | Then I dont now what v is and how you define the 2-norm of v. | |
| Jan 8, 2017 at 15:24 | comment | added | user103308 | no, each $A_i$ can be a matrix, not a column vector. | |
| Jan 8, 2017 at 15:23 | history | edited | user103308 | CC BY-SA 3.0 |
deleted 60 characters in body
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| Jan 8, 2017 at 9:47 | comment | added | user35593 | I don't understand your question. Isn't $\sum A_i v_i=Av$? So eqn (1) simply holdd by definition of the spectral norm. | |
| Jan 7, 2017 at 17:20 | review | First posts | |||
| Jan 7, 2017 at 17:43 | |||||
| Jan 7, 2017 at 17:18 | history | asked | user103308 | CC BY-SA 3.0 |