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Jan 4, 2017 at 3:47 comment added Fan Zheng More generally, $C_f$ is lower bounded by $\sup|\nabla f|$.
Jan 3, 2017 at 23:40 comment added Fan Zheng Remove the absolute value, and you get $\nabla f(0)$.
Jan 3, 2017 at 21:41 history edited Holden Lee CC BY-SA 3.0
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Jan 3, 2017 at 21:16 history edited Holden Lee CC BY-SA 3.0
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Jan 3, 2017 at 21:10 history asked Holden Lee CC BY-SA 3.0