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Dec 31, 2016 at 22:51 history edited Joel David Hamkins CC BY-SA 3.0
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Dec 31, 2016 at 21:03 comment added Joel David Hamkins Correction: I should have said finitely-generated subfield; of course, it is countably infinite.
Dec 31, 2016 at 19:14 comment added Todd Trimble Oh sure; thanks. I rather prefer that formulation.
Dec 31, 2016 at 19:12 comment added Joel David Hamkins One could argue like this: that theory (the elementary diagram of $F$ plus the assertion that $\pi$ is a nontrivial automorphism) is consistent, because every finite part of the theory is consistent, since any finite subtheory makes reference to only finitely many particular elements of $F$, which generate a finite subfield, and then reduce to the computable saturation argument in the countable case. So, no forcing. I think almost any model theory book will prove the existence of sufficiently homogeneous models, and that is what I'm doing.
Dec 31, 2016 at 18:49 comment added Todd Trimble Is it possible to rewrite your penultimate paragraph so as to make no reference to forcing extensions, but instead appeal to pure model theory?
Dec 31, 2016 at 13:22 history edited Joel David Hamkins CC BY-SA 3.0
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Dec 31, 2016 at 13:09 history answered Joel David Hamkins CC BY-SA 3.0