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Dec 30, 2016 at 1:03 comment added Cesare More precisely, the evaluation of $op(\eta,\nu_\eta)$ by $G$ is $op(\eta,\nu_\eta)_G=\langle \eta, X_\eta\rangle$. Since every $A_\nu$ meets $G$ then the evaluation of $\bigcup_\eta\{\{op(\eta,\nu_\eta)\}\times A_\eta\}$ is the function $\{\langle \eta,X_\eta\rangle:\;\eta\in \kappa\}$.
Dec 30, 2016 at 0:53 comment added Cesare It's the name for an ordered pair. I used that to build a name for the sequence $(X_\eta)_\eta$.
Dec 29, 2016 at 19:16 comment added Noah Schweber @Cesare What is "op"?
Dec 29, 2016 at 19:08 comment added Cesare Thank you @NoahSchweber !! But only one more thing: the name for the sequence $(X_\eta)_\eta$ would be $\bigcup_\eta \{\{op(\eta,\nu_\eta)\}\times A_\eta\}$?
Dec 29, 2016 at 19:02 vote accept Cesare
Dec 29, 2016 at 18:53 history edited Noah Schweber CC BY-SA 3.0
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Dec 29, 2016 at 18:46 comment added Noah Schweber @Cesare I was totally wrong, see Miha's comment above. I'm editing my answer now.
Dec 29, 2016 at 18:45 comment added Cesare Of course, Cummings' chapter from the Handbook. It's on page 804.
Dec 29, 2016 at 18:43 comment added Miha Habič There is a subtle issue here: each of the names $\nu_\eta$ is in $M$, but the whole sequence only lives in $V[G]$. You need the extra assumptions on $\mathbb{P}$ to get the sequence itself (or a good enough approximation) in $V$.
Dec 29, 2016 at 18:39 comment added Cesare That was my problem... I reached your same proof but I don't know where $\kappa^+-$cc-ness is expected to appear..
Dec 29, 2016 at 18:34 history answered Noah Schweber CC BY-SA 3.0