Timeline for Getting asymptotic behaviour of an integral?
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| S Jan 8, 2017 at 16:02 | history | bounty ended | PhoenixPerson | ||
| S Jan 8, 2017 at 16:02 | history | notice removed | PhoenixPerson | ||
| Jan 7, 2017 at 10:16 | answer | added | Jan-Christoph Schlage-Puchta | timeline score: 3 | |
| Jan 6, 2017 at 17:10 | answer | added | Bazin | timeline score: 2 | |
| S Jan 1, 2017 at 11:10 | history | bounty started | PhoenixPerson | ||
| S Jan 1, 2017 at 11:10 | history | notice added | PhoenixPerson | Improve details | |
| Dec 30, 2016 at 1:17 | answer | added | COnstructor | timeline score: 0 | |
| Dec 29, 2016 at 19:57 | comment | added | user64494 | @Michael Renardy : Could you elaborate and base your statement? | |
| Dec 29, 2016 at 19:24 | comment | added | Michael Renardy | @user64494: This does not work. if we let $\rho\to 0$ under the integral, the resulting integral diverges! | |
| Dec 29, 2016 at 18:28 | answer | added | Carlo Beenakker | timeline score: 3 | |
| Dec 29, 2016 at 18:07 | comment | added | user64494 | Have you tried to cut the tail of the integral (say, from 10000) and after that to replace $\sin (k\rho)=k\rho-\frac{k^3\rho^3} 6 +O((k\rho)^5)?$ | |
| Dec 29, 2016 at 17:01 | history | asked | PhoenixPerson | CC BY-SA 3.0 |