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S Jan 7, 2017 at 11:03 history bounty ended CommunityBot
S Jan 7, 2017 at 11:03 history notice removed CommunityBot
Jan 7, 2017 at 3:54 history edited Cusp
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Dec 31, 2016 at 1:42 history edited Cusp CC BY-SA 3.0
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Dec 31, 2016 at 1:33 comment added Cusp @IanAgol Thanks for the remark. But I am mostly interested in orientable surfaces.
Dec 30, 2016 at 22:31 comment added Ian Agol This is false for a non-orientable surface, but might be true for orientable surfaces. The point is that the fundamental group of a Klein bottle is given by $\langle x, y | x^2y^2=1\rangle$. This relator is conjugate to $(x*y)*y*x$. So if one takes a punctured Klein bottle, and take $x,y$ to be the appropriate closed curves, then $x*y*y*x$ will be homotopic to the boundary. Then any other closed curve (representing $z$) intersecting $x*y$ will not intersect $x*y*y*x$, the peripheral curve.
S Dec 30, 2016 at 9:49 history bounty started Cusp
S Dec 30, 2016 at 9:49 history notice added Cusp Draw attention
Dec 28, 2016 at 15:24 history edited Cusp CC BY-SA 3.0
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Dec 28, 2016 at 15:09 history edited YCor
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Dec 28, 2016 at 14:21 comment added Cusp @HJRW Yes. It is the multiplication of the fundamental group.
Dec 28, 2016 at 14:17 comment added HJRW Does $*$ denote concatenation?
Dec 28, 2016 at 14:14 history edited Cusp CC BY-SA 3.0
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Dec 28, 2016 at 14:06 history undeleted Cusp
Dec 28, 2016 at 9:31 history deleted Cusp via Vote
Dec 28, 2016 at 7:41 history asked Cusp CC BY-SA 3.0