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Dec 27, 2016 at 20:04 comment added Jean Duchon Apply the chain rule; $\nabla(f\circ v)=f'(v)\nabla v$.
Dec 27, 2016 at 19:49 comment added Vrouvrou I man how we see that we must choose this condition
Dec 27, 2016 at 17:22 comment added Jean Duchon Lipschitz continuity: $\sup_{s<t}|\frac{f(s)-f(t)}{s-t}|<\infty$
Dec 27, 2016 at 17:14 comment added Vrouvrou and how we find that $f'\in L^{\infty}$ please
Dec 27, 2016 at 17:11 comment added Jean Duchon No, Bazin is right: for polynomials, only affine functions (polynomials of degree 1) work for $N\ge2$.
Dec 27, 2016 at 17:06 history edited Jean Duchon CC BY-SA 3.0
correction
Dec 27, 2016 at 16:47 comment added Vrouvrou this answer is on contradiction with the answer of @Bazin no?
Dec 27, 2016 at 16:41 history answered Jean Duchon CC BY-SA 3.0