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Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Dec 26, 2016 at 16:38 history edited Qfwfq CC BY-SA 3.0
edited body
Dec 25, 2016 at 18:41 comment added Oscar Randal-Williams By embedding a finite CW complex in Euclidean space, thickening it up to a (framed) manifold, and taking its double, you can get any betti numbers but have trivial tangent bundle and hence trivial characteristic classes.
Dec 25, 2016 at 18:40 answer added Qiaochu Yuan timeline score: 17
Dec 25, 2016 at 18:38 comment added Gregory Arone Characteristic numbers are cobordism invariant, but Betti numbers are not.
Dec 25, 2016 at 18:08 history asked Qfwfq CC BY-SA 3.0