Timeline for Endomorphism of Brandt Semigroup $B_n(G)$, where $G$ is a finite group
Current License: CC BY-SA 3.0
9 events
when toggle format | what | by | license | comment | |
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Dec 21, 2016 at 18:31 | vote | accept | user120386 | ||
Dec 21, 2016 at 18:17 | comment | added | user120386 | I know that if we define $g : G \rightarrow G$ such that $(1,a,1) \theta = (1\sigma , ga ,1\sigma)$. is an endomorphism on $G$ and $\theta \ \ \in \ \ End(B_n(G))$. | |
Dec 21, 2016 at 18:13 | comment | added | user120386 | Since $(i,a,j) = (i,1,1) (1,a,1) (1,1,j)$ and $(1,a,1)$ maps to $(1 \sigma, ga , 1\sigma)$ and if $(i,1,1)$ maps to $(i \sigma , b , 1 \sigma)$ implies $(1,1,i)$ maps to $(1 \sigma , b^{-1} , i \sigma)$. But what is the image of $(i,1,1)$. | |
Dec 21, 2016 at 17:35 | answer | added | Benjamin Steinberg | timeline score: 3 | |
Dec 21, 2016 at 17:30 | comment | added | Benjamin Steinberg | You are missing one ingredient in your formulation, conjugation by a diagonal matrix. | |
Dec 21, 2016 at 17:24 | comment | added | Benjamin Steinberg | I will write up the proper answer and erase the comments. | |
Dec 21, 2016 at 16:21 | comment | added | user120386 | @ Benjamin : How we can write every element (i,a,j) is the product of the elements $(j,1,j)$ and $(1,a,1)$, where $j \in \ \ [n]$ and $a \in \ \ G$. | |
Dec 21, 2016 at 10:20 | review | First posts | |||
Dec 21, 2016 at 10:23 | |||||
Dec 21, 2016 at 10:15 | history | asked | user120386 | CC BY-SA 3.0 |