Timeline for Cool problems to impress students with group theory
Current License: CC BY-SA 2.5
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 1, 2015 at 21:56 | comment | added | LSpice | For your original (2), 'their' refers to the child, right? "[T]he type of a person's parents can be determined by [that person's] gender and type." For the rephrased (2), don't you mean that $s$ and $d$ are permutations? (I suppose that you can call a permutation an integer action, but the terminology seems unusual.) | |
| Mar 26, 2011 at 21:33 | comment | added | Brad Rodgers | Sorry to take so long to respond. My memory isn't fresh, so I can't remember what I was thinking -- if anything -- in saying "s must be (12) (it cannot be e)," but it seems to me you are right. It is still true in this case that the group generated by s and d is commutative, for all that it's worth. | |
| Jan 28, 2011 at 22:10 | comment | added | Eric Hall | I'm not seeing why we can't have just two types with s=(1 2) and d=e. | |
| May 24, 2010 at 7:30 | comment | added | Gunnar Þór Magnússon | There is also a short informal discussion of this problem in "The artist and the mathematician" by Amir D. Aczel. | |
| May 24, 2010 at 3:39 | history | answered | Brad Rodgers | CC BY-SA 2.5 |