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Apr 7, 2017 at 8:26 vote accept co.sine
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Apr 5, 2017 at 12:27 answer added domotorp timeline score: 5
Apr 5, 2017 at 12:17 history edited domotorp CC BY-SA 3.0
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Apr 2, 2017 at 10:18 history edited co.sine CC BY-SA 3.0
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S Apr 1, 2017 at 13:36 history bounty started co.sine
S Apr 1, 2017 at 13:36 history notice added co.sine Draw attention
Mar 29, 2017 at 6:00 comment added co.sine @Todd: Apologize, totally my bad. Guess I got too enthusiastic about getting an answer.
Mar 25, 2017 at 13:44 comment added Todd Trimble Okay, a flag was raised over the entirely unnecessary edits. Please don't do that, as this bumps other questions off the front page which also deserve consideration.
Mar 25, 2017 at 12:46 history edited co.sine CC BY-SA 3.0
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Mar 20, 2017 at 1:55 answer added Ryan O'Donnell timeline score: 2
Mar 19, 2017 at 15:15 history edited co.sine CC BY-SA 3.0
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Mar 18, 2017 at 18:20 history edited co.sine CC BY-SA 3.0
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Dec 23, 2016 at 14:48 comment added domotorp Pick a vertex $v$ and let the value at each vertex equal $(-1)^d$ where $d$ is its distance from $v$. In phase $i$ all vertices at distance $i$ are updated, then all vertices at distance $i-1$ and so on, until $v$.
Dec 23, 2016 at 10:13 comment added co.sine @domotorp: what is the example on an infinite $3$-regular tree, where a deterministic sequence of updates leads to infinitely many changes at a vertex?
Dec 16, 2016 at 10:03 comment added domotorp @Kevin: It's easy to give such an example on an infinite $3$-regular tree. I don't know whether this is an example to the original question. In any frozen configuration each constant-valued component most be infinite.
Dec 16, 2016 at 10:01 comment added domotorp This model seems to be very similar to the Glauber dynamics of the Ising model.
Dec 16, 2016 at 9:34 comment added domotorp @Anthony: Why couldn't the system freeze in some other state? I think if everyone has a neighbor with whom it shares its value, then there are no more changes.
Dec 16, 2016 at 8:51 comment added Anthony Quas This is an example of a voter model. I know that the answer is yes for the synchronous voter model (where all clocks tick once per second). Indeed: take $\mathbb Z$ with a uniform i.i.d. distribution of $\pm 1$ at the vertices. Then the set of configurations that converge to all 1's is invariant (so of measure 0 or 1); ditto for the configurations that converge to all $-1$'s. By symmetry, they are both of measure 0. From this, it follows that almost surely, each vertex oscillates infinitely often.
Dec 16, 2016 at 7:36 comment added Kevin P. Costello Is there an easy example of a graph and a deterministic sequence of updates on it that would cause a vertex to change values infinitely often?
Dec 16, 2016 at 7:26 comment added user83457 On a circle let plus and minus alternate. then no one will ever decide to change.
Dec 16, 2016 at 6:55 review First posts
Dec 16, 2016 at 7:19
Dec 16, 2016 at 6:53 history asked co.sine CC BY-SA 3.0