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Dec 15, 2016 at 22:22 comment added Dima Pasechnik Isotropic forms are easy and fun to deal with over finite fields. And you might connect the particular case of $U_4(\mathbb{F}_2)$ to 27 lines on cubic surfaces...
Dec 15, 2016 at 21:02 answer added Noam D. Elkies timeline score: 1
Dec 15, 2016 at 20:33 history edited LSpice
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Dec 15, 2016 at 19:43 history made wiki Post Made Community Wiki by Todd Trimble
Dec 15, 2016 at 19:43 comment added Todd Trimble Made CW according to the OP's wishes (people are encouraged to tweak or extend or correct it).
Dec 15, 2016 at 19:31 answer added Will Jagy timeline score: 4
Dec 15, 2016 at 18:26 comment added Noam D. Elkies also (and possibly more suitable for undergraduates) the determinant of a 2-by-2 matrix, and trace(A^2) for square matrices of any order, are natural quadratic forms that represent zero. And a conic plane curve is basically a quadratic form in 3 real variables that represents zero (up to multiplying the form by a nonzero scalar). If it has rational coefficients then the existence of rational points is equivalent to the question of whether the form represents zero nontrivially over the rationals.
Dec 15, 2016 at 18:24 comment added Noam D. Elkies "Isotropic" = forms that represent zero? Sure; they often arise as intersection forms on algebraic surfaces (e.g. an elliptic fibration yields a nontrivial divisor with self-intersection zero), and are often useful to describe the structure of positive-definite forms (quite a few examples in Conway and Sloane's "SPLAG" = *Sphere Packings, Lattices, and Groups").
Dec 15, 2016 at 18:12 history asked Jean Raimbault CC BY-SA 3.0