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Apr 13, 2017 at 12:58 history edited CommunityBot
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Dec 14, 2016 at 15:45 comment added David Pokorny $\exists v\,\forall x\, x\in v$ is not true in all models of $T_0$ but it is in all models of $T_1$.
Dec 14, 2016 at 7:34 review Close votes
Dec 14, 2016 at 15:49
Dec 14, 2016 at 4:48 comment added Noah Schweber In what sense is $T_0\not=T_1$, if $T_1=T_2$? (Note that in my original answer where I said that the hierarchy collapses immediately in a sense, my indexing was wrong: $T_0$ is already "essentially the same as" $T_1$, in a precise sense; and I've edited that.)
Dec 14, 2016 at 2:44 comment added David Pokorny Okay, it looks like $T_0 \not= T_1$ and $T_1 = T_2 = T_\Omega$.
Dec 14, 2016 at 2:28 history edited David Pokorny CC BY-SA 3.0
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Dec 14, 2016 at 2:00 answer added Joel David Hamkins timeline score: 3
Dec 14, 2016 at 1:56 answer added Noah Schweber timeline score: 2
Dec 13, 2016 at 23:46 history asked David Pokorny CC BY-SA 3.0