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May 17, 2017 at 12:37 comment added Todd Trimble I would have migrated this to Math.SE, except that it's too old to migrate.
May 17, 2017 at 12:36 history closed Todd Trimble Not suitable for this site
May 17, 2017 at 12:36 history reopened Todd Trimble
Dec 12, 2016 at 8:39 comment added Amin235 By Frobenius normal form of your adjacency matrix, the isomorphic of your graph is digraph G { 2 -> 1 2 -> 4 3 -> 2 4 -> 3 }
Dec 12, 2016 at 3:06 history closed Qiaochu Yuan
Yemon Choi
Willie Wong
Jeremy Rickard
R W
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Dec 12, 2016 at 0:04 review Close votes
Dec 12, 2016 at 3:12
Dec 12, 2016 at 0:02 answer added Rodrigo de Azevedo timeline score: 5
S Dec 11, 2016 at 23:58 history suggested Rodrigo de Azevedo CC BY-SA 3.0
minor edits
Dec 11, 2016 at 23:33 answer added Igor Rivin timeline score: 6
Dec 11, 2016 at 23:30 review Suggested edits
S Dec 11, 2016 at 23:58
Dec 11, 2016 at 23:24 review First posts
Dec 12, 2016 at 0:12
Dec 11, 2016 at 23:21 history asked stealingbikes CC BY-SA 3.0