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Dec 19, 2016 at 23:43 history edited paul garrett CC BY-SA 3.0
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Dec 9, 2016 at 19:27 vote accept Desiderius Severus
Dec 9, 2016 at 16:56 answer added Kimball timeline score: 9
Dec 9, 2016 at 11:32 comment added GH from MO The "conductor of Iwaniec-Sarnak" is not called the conductor, but the analytic conductor. At any rate, thanks for clarifying the question.
Dec 9, 2016 at 11:15 comment added Desiderius Severus @GHfromMO I just edited my post: the $\pi$'s are representations of the group of units of a totally definite quaternion algebra (so compact modulo the center), and the $c(\pi)$ is the usual notion of conductor of Iwaniec-Sarnak, lifted from $GL_2$ to $B^\times$.
Dec 9, 2016 at 11:14 history edited Desiderius Severus CC BY-SA 3.0
Precision on which kind of automorphic representations
Dec 9, 2016 at 11:12 comment added GH from MO Please be more specific. What kind of $\pi$'s are you looking at? There are many (reductive algebraic) groups, and many kinds of automorphic representations. Also, clarify what exactly you mean by $c(\pi)$.
Dec 9, 2016 at 11:10 history edited GH from MO
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Dec 9, 2016 at 10:52 history asked Desiderius Severus CC BY-SA 3.0